PZ HELP Find the magnitude of the horizontal and vertical components of a force of 465 newtons at a bearing of 19° from the horizontal. Round to the nearest whole number.

horizontal component: 440 N, vertical component: 151 N

horizontal component: 440 N, vertical component: 25 N

horizontal component: 151 N, vertical component: 314 N

horizontal component: 151 N, vertical component: 440 N

The answer to your question is the first choice

Step-by-step explanation:

Data

Force = 465 N

bearing = 19°

Process

1.- Find the components using trigonometric functions

To find the horizontal component use cosine

To find the vertical component use sine

            cos Ф = x/F                     sin Ф = y/F

Substitution

            cos 19 = x/465                sin 19 = y/465

            x = 465 cos 19                  y = 465 sin 19

            x = 439 N                          y = 151.39 N

2.- Rounding to the nearest number

Horizontal component = 440N

Vertical component = 151 N            

2. angles qrt and qst both measures 156 degrees.

step-by-step explanation:  

we have been given a diagram of a circle and we are told that measure of arc qvt is 156 degrees.  

we can see from our given diagram that angle qrt and angle qst subtends to arc qvt.

since we know that angles subtended by the same arc at the circumference are always equal.

by angle subtended by same arc theorem, measure of angle qrt and angle qst will be equal to the measure of arc qvt.

therefore, angles qrt and qst both measures 156 degrees and 2nd statement is the correct choice.

answer: a. 13/44

step-by-step explanation: judging by the information given to us, we are looking for experimental probability. we can see that 13 males have chosen chocolate ice cream. there are 44 ice creams in total (remember that the total is always the denominator). so our answer is 13/44.