Let W be a random variable giving the number of heads minus the number of tails in three tosses of a coin. List the elements of the sample space S for the three tosses of the coin and to each sample point assign a value w of W.

HHH, W = 3-0 = 3

HHT, W= 2-1=1

HTH, W= 2-1=1

THH, W=2-1 =1

HTT, W= 1-2=-1

THT, W= 1-2=-1

TTH, W=1-2=-1

TTT, W=0-3 = -3

So then the sample space for W is:

Just 4 possible values from 8 possible combinations for the 3 random tosses

Step-by-step explanation:

For this case we define W as the random variable who represent the number of heads minus the number of tails in three tosses of a coin.

W= # heads- # coins

Since we toss a coin 3 times we have 2*2*2= 8 possible results. We can list the results and the corresponding values for W like this:

HHH, W = 3-0 = 3

HHT, W= 2-1=1

HTH, W= 2-1=1

THH, W=2-1 =1

HTT, W= 1-2=-1

THT, W= 1-2=-1

TTH, W=1-2=-1

TTT, W=0-3 = -3

So then the sample space for W is:

Just 4 possible values from 8 possible combinations for the 3 random tosses

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)

y = 5x + 17

step-by-step explanation:

a perpendicular line will be the opposite reciprocal slope of the given equation.   the slope given is -1/5 so the opposite reciprocal is 5

find b:

7 = 5 (-2) + b

7 = -10 + b

17 = b

write equation

y = 5x + 17