To reach a campsite, a hiker first walks for 2 mi at a bearing of N 40° E. Then he walks 3 mi due east. What are the magnitude and direction of his hike from his starting point to the campsite? Round the distance to the nearest tenth of a mile and the direction to the nearest degree.

4.55 mi N70°E, or 4.6 mi n70°E

Step-by-step explanation:

Draw a diagram; it helps keep the trig functions straight.

Starting from (0,0) a walk of 2 mi at N40°E leaves him at

x = 2sin40° = 1.29

y = 2cos40° = 1.53

Now, a walk 3 mi due east leaves him at

(4.29,1.53)

The new bearing is an angle θ with tanθ = 4.29/1.53 = 2.80

so, the new location is 4.55 mi N70°E

9.55 degrees.

step-by-step explanation:

the given angle is

1 cycle is equal to 2π radians. so 4π will be equal to two cycles.

5.166667π-4π = 1.166667π

hence, this angle goes a little more than negative x axis.

1.166667π-π= 0.166667π

hence, the reference angle is 0.166667π radians.

1 radian = 57.2958 degrees

now, in degrees, this should be equals to 9.55 degrees.