What are the zeros of y=4x^2+3x-1?

The zeros are x = 1 /4 or

x = -1

Step-by-step explanation:

The given equation is expressed as

y = 4x² + 3x - 1

To determine the zeros of the quadratic equation, we would equate it to zero first. It becomes

4x² + 3x - 1 = 0

We would apply the method of factorization. We would find two numbers such that their sum or difference is 3x and their product is - 4x². The two numbers are 4x and

- x. Therefore,

4x² + 4x - x - 1 = 0

4x(x + 1) - 1(x + 1) = 0

4x - 1 = 0 or x + 1 = 0

x = 1 /4 or x = -1

answer: sensy

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