In 6 hours a boat, traveling with the current, covers 20 more mi than in 10 hours, traveling against the current. What is the speed of the current if the speed of the boat in still water is 15 mph?

The speed of current is 5 miles per hour.

Step-by-step explanation:

Given:

In 6 hours a boat, traveling with the current, covers 20 more mi than in 10 hours, traveling against the current.

If the speed of the boat in still water is 15 mph.

Now, to find the speed of the current.

Let the speed of current be

So, the speed of the boat going with current =

And, the speed of the boat going against current =

Let the distance travelled against the current be

So, the distance travelled with the current =

As, the time is given with the current = 6 hours.

And, the time against the current = 10 hours.

Now, to get the distance of boat travelled with the current:

Subtracting 20 on both sides we get:

Subtracting 6 on both sides we get:

    .......( 1 )

Now, to get the distance of boat travelled against the current:

Adding 10 on both sides we get:

  .......( 2 )

Now, by using elimination method we subtract equation ( 1 ) from equation ( 2 ):

Dividing both sides by 16 we get:

.

Therefore, the speed of current is 5 miles per hour.

(x3 + 6x2 + 2x - 6) • (x - 1)

step-by-step explanation:

polynomial long division :

3.2     polynomial long division

dividing :   x4+5x3-4x2-8x+6

                              ("dividend")

by         :     x-1     ("divisor")

dividend     x4   +   5x3   -   4x2   -   8x   +   6

- divisor   * x3     x4   -   x3            

remainder         6x3   -   4x2   -   8x   +   6

- divisor   * 6x2         6x3   -   6x2        

remainder             2x2   -   8x   +   6

- divisor   * 2x1             2x2   -   2x    

remainder               -   6x   +   6

- divisor   * -6x0               -   6x   +   6

remainder                     0

quotient :   x3+6x2+2x-6   remainder:   0

20

step-by-step explanation: