Xfavor algien que me ayude la pregunta 5.6 .7 .8 es de urgencia
por favor chicos

Part 5) The maximum value of z is 110.7

Part 6) The maximum value of z is 6

Part 7) The minimum value of z is 120

Part 8 The minimum value of z is 3

Step-by-step explanation:

Part 5) Maximizes function z subject to constraints

----> constraints A

 ---> constraints B

---> constraints C

---> constraints D

using a graphing tool

The solution is the  shaded area

The vertices of the shaded area are

(0,0),(2,0),(15.7,4.6) and (0,15)

see the attached figure N 1

Substitute the value of x and the value of y of each vertex in the objective function z and then compare the results

For (0,0) ---->

For (2,0) ---->

For (15.7,4.6) ---->

For (0,17) ---->

therefore

The maximum value of z is 110.7

Part 6) Maximizes function z subject to constraints

----> constraints A

 ---> constraints B

---> constraints C

---> constraints D

using a graphing tool

The solution is the  shaded area

The vertices of the shaded area are

(0,0),(3,0),(0.5,2.5) and (0,2)

see the attached figure N 2

Substitute the value of x and the value of y of each vertex in the objective function z and then compare the results

For (0,0) ---->

For (3,0) ---->  

For (0.5,2.5) ---->

For (0,2) ---->

therefore

The maximum value of z is 6

Part 7) Minimize function z subject to constraints

----> constraints A

 ---> constraints B

--> constraints C

---> constraints D

---> constraints E

using a graphing tool

The solution is the  shaded area

The vertices of the shaded area are

(0,100),(20,50),(40,20) and (80,0)

see the attached figure N 3

Substitute the value of x and the value of y of each vertex in the objective function z and then compare the results

For (0,100) ---->

For (20,50) ---->  

For (40,20) ---->

For (80,0) ---->

therefore

The minimum value of z is 120

Part 8) Minimize function z subject to constraints

----> constraints A

 ---> constraints B

--> constraints C

---> constraints D

---> constraints E

using a graphing tool

The solution is the  line segment (0,1) to (4,5)

see the attached figure N 4

Substitute the value of x and the value of y of each endpoint in the objective function z and then compare the results

For (0,1) ---->

For (4,5) ---->

therefore

The minimum value of z is 3

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step-by-step explanation: