Mathematics, 27.02.2020 02:49 alani64

The carbon dioxide emissions of a group of nations had a mean of 8.7 and standard deviation of 2.1. a. One country's observation was 14.1. Find its z-score and interpret. b. Another country's observation was 2.2. Find its z-score and interpret. c. A third country's observation was 9.1. Find its z-score and interpret.

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Answer from: JvGaming2001

a) Z = 2.57

This country emmits 2.57 standard deviations above the mean of the emissions of the countries of this group of nations.

b) Z = -3.1

This country emmits 3.1 standard deviations below the mean of the emissions of the countries of this group of nations.

c) Z = 0.19

This country emmits 0.19 standard deviations above the mean of the emissions of the countries of this group of nations.

Step-by-step explanation:

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 8.7, \sigma = 2.1$

a. One country's observation was 14.1. Find its z-score and interpret.

Here we have X = 14.1

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{14.1 - 8.7}{2.1}$

Z = 2.57

This country emmits 2.57 standard deviations above the mean of the emissions of the countries of this group of nations.

b. Another country's observation was 2.2. Find its z-score and interpret.

Here we have X = 2.2

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{2.2 - 8.7}{2.1}$

Z = -3.1

This country emmits 3.1 standard deviations below the mean of the emissions of the countries of this group of nations.

c. A third country's observation was 9.1. Find its z-score and interpret.

Here we have X = 9.1

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{9.1 - 8.7}{2.1}$

Z = 0.19

This country emmits 0.19 standard deviations above the mean of the emissions of the countries of this group of nations.

Answer from: Quest

The answer would be b

Answer from: Quest

Answer: the correct answer is 10step-by-step explanation: let the number be n, then the expression becomes,then“twelve more than the quotient of a number and two, decreased by four” is $(\frac{n}{2}+12)-4$ when n=4,we substitute 4 whetever we see n to get, $(\frac{4}{2}+12)-4$ we simplify to obtain, $=(2+12)-4$ we further simplify to get, $=14-4=10$ therefore the correct answer is c.

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