A 10 gauge copper wire carries a current of 26 A. Assuming one free electron per copper atom, calculate the magnitude of the drift velocity of the electrons.

-3.71 * 10^-4 m/s

Step-by-step explanation:

A 10 gauge copper wire has a standard cross sectional area of 5.26

=

density of copper,  is 8.80 × 103 kg/m3

The atomic mass of copper is 63.54 * 10^-3 Kg/mol.

Avogadro’s number, 6.02 × 1023 atoms/mol

Density of copper's free electrons =

= 8.3374 * 10^28

drift velocity of the electrons =

step-by-step explanation:

the areas of two similar triangles are 18 cm2 and 8 cm2. one of the sides of the first triangle is 4.5 cm. what is the length of the corresponding side of the other triangle?