In Jesus name please help me

Expression J:

–12 ÷ (–3) – 20 ÷ 2 has a value of –6.

Solution:

To find which expression has a value of –6.

Solve these expressions using BODMAS rule.

Expression F: –4 · 2 – (–14)

–4 · 2 – (–14) = –4 · 2 + 14

                      = –8 + 14

                      = 6

Therefore, this is not true.

Expression G: –16 ÷ (–2) – (–2)

First do division by BODMAS rule.

–16 ÷ (–2) – (–2) = 8 – (–2)

                           = 8 + 2

                           = 10

Therefore, this is not true.

Expression H: –2 – (–8) ÷ (–1)

First do division by BODMAS rule.

–2 – (–8) ÷ (–1) = –2 – 8

                         = –10

Therefore, this is not true.

Expression J: –12 ÷ (–3) – 20 ÷ 2

First do division by BODMAS rule.

–12 ÷ (–3) – 20 ÷ 2 = 4 – 20 ÷ 2

                               = 4 – 10

                               = –6

This expression has a value of –6.

Hence it is true.

Therefore –12 ÷ (–3) – 20 ÷ 2 has a value of –6.

4400

step-by-step explanation:

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

step-by-step explanation:

given   that triangle lno is congruent to triangle lnm.

we have to fill up the blanks in the given question.

according to above order of congruency   kept in mind we can say that

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

ln ≅ ln due to common in both.

hence, by sas congruency,

the side angle side rule   states that if two sides and the included angle of one triangle are congruent to another triangle, then these two triangles are congruent.