In MNLP, NP bisects ∠MNL. Is this enough information to prove that MNLP is a rhombus? Explain.

A. Yes, by Theorem 6−17
B. Yes, because it proves that MNLP is a rectangle, and any rectangle is also a rhombus.
C. No; you also need to know MNLP is a parallelogram and that ∠MNL is supplementary to ∠PMN.
D. No; you also need to know that MNLP is a parallelogram and that NP bisects ∠LPM.

step-by-step explanation:

if you meant, "on the way from (3, 2) to (3, 14):

x does not change; y increases by 12.

ensure that you have copied down this problem correctly.   .

2/3x + 7 = 29

step-by-step explanation:

two thirds = 2/3

plus a number = x

at least 29 = 29

there for you should get 2/3x + 7 = 29

(1, –1), (16, –4), (36, –6)

step-by-step explanation:

given that the function is

this can also be written as

we have to graph this function and check which list of points lie on the graph

see attachment for graph:

we find that the points lying are (1,-1) (16,-4) and (36,-6)

since square root is there we find that x can only be posiitve but y can be since square root both positive and negative.