Suppose you carry out a significance test of H0: μ = 3.5 versus Ha: μ < 3.5 based on sample size n = 17 and obtain t = –3.4. Find the p-value for this test. What conclusion can you draw at the 5% significance level? Explain. a. The p-value is 0.4982. We reject H0 at the 5% significance level because the p-value 0.4982 is greater than 0.05.b. The p-value is 0.4982. We fail to reject H0 at the 5% significance level because the p-value 0.4982 is greater than 0.05.c. The p-value is 0.5018. We fail to reject H0 at the 5% significance level because the p-value 0.5018 is greater than 0.05.d. The p-value is 0.0018. We reject H0 at the 5% significance level because the p-value 0.0018 is less than 0.05.e. The p-value is 0.0018. We fail to reject H0 at the 5% significance level because the p-value 0.0018 is less than 0.05.

We reject H0 at the 5% significance level because the p-value 0.0018 is less than 0.05 is the correct answer here.

Step-by-step explanation:

For n - 1= 16 degrees of freedom, we get from the t distribution tables for this one tailed test the p-value as:

p = P( t16 < -3.4) = 0.0018

As the p-value here is 0.0018 < 0.05 which is the level of significance, therefore the test is significant and we can reject the null hypothesis here. Therefore The p-value is 0.0018. We reject H0 at the 5% significance level because the p-value 0.0018 is less than 0.05 is the correct answer here.

hello from mrbilldoesmath!

answer:

a(n) - a(n-1) -3

discussion:

this ones a bit interesting. given a(n) = 5 - 3n consider this:

a(n-1) = 5 - 3(n-1)

          = (5 - 3n) + 3             => but a(n) = 5 - 3n, the first term

          = a(n)   + 3                 => subtract 3 from both sides

a(n-1) -3 = a(n)  

or

a(n) - a(n-1) -3

you,

mrb

none cuz there are no "following statements" regarding the question

step-by-step explanation: