Solve for t. d= -16t^2 + 4t

I’m suck on this problem for some reason

Thank you!

t = 1/8 ± √(1 − 4d) / 8

Step-by-step explanation:

d = -16t² + 4t

Move everything to the left side:

16t² − 4t + d = 0

Solve with quadratic formula:

t = [ -(-4) ± √((-4)² − 4(16)(d)) ] / 2(16)

t = [ 4 ± √(16 − 64d) ] / 32

t = [ 4 ± 4√(1 − 4d) ] / 32

t = [ 1 ± √(1 − 4d) ] / 8

t = 1/8 ± √(1 − 4d) / 8

a, b, c, d are correct.

step-by-step explanation:

we have g(x) = 3 and are required to find which option is a translation of g(x).

now, 'translation' is a transformation which means to shift the function in any direction and the general form of translation is g(x) + k, where k is any real number.

so, according to the options we see that all are correct as they satisfy the general form of translation.

also, it can be seen from the graph below that the function g(x) = 3 is shifted from its position in all the four options.