3x-6y=27 and 6x+9y=-30 solve this system of linear equations

x= 1 and y= -4

Step-by-step explanation:

3x-6y=27

3(x-2y)=27

divide both sides by 3

x-2y=9 ->eq 1

6x+9y=-30

3(2x+3y)=-30

divide both sides by 3

2x+3y=-10 ->eq 2

multiply eq 1 by 2

2x-4y=18 -> eq 3

now subtract eq 3 from eq 2

  2x + 3y= -10

 ± 2x + 4y= ±18  (-4y becomes +4y after changing sign due to subtraction)

     7y = -28

     y = -4    by dividing 7 on both sides

put value of y in eq 1

x-2(-4)=9

x+8=9

x= 9 - 8

x= 1

x/7.50 = 15

x= 7.50 / 15 divide

step-by-step explanation:

arithmetic sequence: a sequnce in which the diffrence between any two consecutive terms is the same

step-by-step explanation: