Domain and range from graph
Problem
What is the domain of hhh?

Choose 1
Choose 1

(Choice A)
A
-7 \leq x \leq 4−7≤x≤4minus, 7, is less than or equal to, x, is less than or equal to, 4

(Choice B)
B
-2 \leq x \leq 7−2≤x≤7minus, 2, is less than or equal to, x, is less than or equal to, 7

(Choice C)
C
The xxx-values -2−2minus, 2, 333, 666, and 777

(Choice D)
D
The xxx-values -7−7minus, 7, -3−3minus, 3, -1−1minus, 1, 111, and 44

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)

8p+(-9)

(-9)3p+5p and you can swith em around

263.5

step-by-step explanation:

7.75(17)= 131.75     < (2) = 263.5