Gabe Amodeo, a nuclear physicist, needs 80 liters of a 30% acid solution. He currently has a 20 % solution and a 60 % solution. How many liters of each does he need to make the needed 80 liters of 30% acid solution?

Solution:

Let "x" be the liters of 20 % solution

Then, (80 - x) is the liters of 60 % solution

Final mixture is 80 liters of 30 % solution

Therefore,

"x" liters of 20 % solution and 80 - x liters of 60 % solution is mixed to get 80 liters of 30 % solution

Thus a equation is framed as:

Thus, 60 liters of 20 % solution

Then, (80 - x) = 80 - 60 = 20

20 liters of 60 % solution

c. 4 and 1/2 pounds is the answer! : )