Two assembly lines I and II have the same rate of defectives in their production of voltage regulators. Six regulators are sampled from each line and tested. Among the total of twelve tested regulators, four are defective. Find the probability that exactly two of the defective regulators came from line I. (Round your answer to four decimal places.)

0.4546

Step-by-step explanation:

nCr = n!/(n-r)!r!

Number of ways of selecting the four defective voltage regulators from 12 =  12C4 = 12!/(12-4)!4! = 12!/8!4! = (12 *11*10*9)/(4*3*2*1)

12C4 =  495 ways

Number of ways of selecting 2 defectives from line 1 = 6C2 * 6C2

6C2 = 6!/(6-2)!2! = 6!/4!2! = (6*5)/(2*1) = 15

6C2 * 6C2 = 15*15 = 225 ways

Probability = Number of possible outcomes/ Number of total outcomes

Probability that exactly 2 of the defective regulators came from line 1 = 225/40.95 = 0.4546

there are 70 more legs than eyes at the dog show (196 – 126 = 70). dogs have two more legs than eyes, and humans have the same number of legs as eyes. thus 70 is twice the number of dogs at the show, so the number of dogs is half of 70, which is 35. to get the number of humans, subtract 35 from 63: 63 – 35 = 28.

step-by-step explanation:

i believe that the slope of the line is -5

step-by-step explanation: