When you reverse the digits in a certain two-digit you increase its value by 36. What is the number if the sum of its digits is 10

hello from mrbilldoesmath!

answer:

a(n) - a(n-1) -3

discussion:

this ones a bit interesting. given a(n) = 5 - 3n consider this:

a(n-1) = 5 - 3(n-1)

          = (5 - 3n) + 3             => but a(n) = 5 - 3n, the first term

          = a(n)   + 3                 => subtract 3 from both sides

a(n-1) -3 = a(n)  

or

a(n) - a(n-1) -3

you,

mrb

22 dimes and 9 nickels

step-by-step explanation:

29.5977692753

step-by-step explanation:

b

step-by-step explanation: