Mathematics, 28.02.2020 19:33 miner12924owhu4d
The variable $x$ varies directly as the square of $y$, and $y$ varies directly as the cube of $z$. If $x$ equals $-16$ when $z$ equals 2, what is the value of $x$ when $z$ equals $\frac{1}{2}$?
Answers: 1
varies directly as 
, then there is some constant 
for which
such that
when 
, we have
, we get
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The variable $x$ varies directly as the square of $y$, and $y$ varies directly as the cube of $z$. I...
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