HELP PLS. i do not know how to solve this.

X=50°

Step-by-step explanation:

Let, the fourth angle in the quadrilateral be ∠A

The sum of all the four angles of the quadrilateral is 360°

So 40° + 110°+80°+∠A=360°

230°+∠A=360°

∠A=360°-230°

∠A=130°

The fourth angle of the quadrilateral is 130°

The angle A and X are the angles on a straight line

The sum of the angles on a straight line is 180°

so, ∠A+∠X=180°

130°+∠X=180°

∠X=180°-130°

X=50°

Yo sup??

first we will find the missing angle of polygon

let it be y

y+110+80+40=360

y=130

now

y+x=180

x=180-130

=50

Hope this helps

the value of v.w= -12.

step-by-step explanation:

we are given three vector r,v and w as:

r = < 5, -5, -2> ; v = < 2, -8, -8> ; w = < -2, 6, -5>

we know that r,v and w could also be represented as:

r=5i-5j-2k

v=2i-8j-8k

and w= -2i+6j-5k

where i,j and k are the unit vectors of x,y and z-axis respectively.

also we know that it has the following property:

i.i=1 ; j.j=1; k.k=1

and i.=j.i=i.k=k.i=j.k=k.j=0

i.e. when we multiply two vectors or we find it's dot product we need to only multiply the components of x coordinates with each other; y with each other and z with each other.

hence, v.w= (2i-8j- -2i+6j-5k)

                  = 2×(-2)+(-8)×(6)+(-8)×(-5)

                  = -4-48+40

                  = -12

hence, v.w= -12

44

step-by-step explanation: