Saint Petersburg, Russia and Anchorage, Alaska, both have approximately the same latitude of 60 degrees. That means you can reach Saint Petersburg from Anchorage by flying directly east, or directly west. Assume the earth is a sphere of radius 6371 km. (a) By heading directly east, what is the distance from Anchorage (longitude 150 degrees W) to Saint Petersburg (longitude 30 degrees E)?

Distance from Anchorage (longitude 150 degrees W) to Saint Petersburg (longitude 30 degrees E) = 10,002.47 KM

Step-by-step explanation:

As earth is a sphere of radius 6371 km.

Therefore at 60 degree latitude, the radius of circle can be calculated as shown below:

= 6371 * Cos 60

= 3185.5 KM

Saint Petersburg is nearly 180 degree about Anchorage by flying directly east.

So Distance from Anchorage (longitude 150 degrees W) to Saint Petersburg (longitude 30 degrees E) can be calculated as shown below:

= (180 * 2 * 3.1416 * 3185.5) / 360

= 10,002.47 KM

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3

29.5977692753

step-by-step explanation: