Determine whether each of these sets is nite, countably in nite, or uncount- able. For those that are countably in nite, exhibit a one-to-one correspondence between the set of positive integers and that set. For those that are nite or uncountable, explain your reasoning. a. integers that are divisible by 7 or divisible by 10?

Integers that are divisible by 7 are countably infinite

The set are {7, 14, 21, 28, 35, 42, 49,

Integers that are divisible by 10 are countably infinite

The set are {10, 20, 30, 40, 50, 60, 70,

Also for the negative integers divisible by 7 or 10{,-49, -42, -35, -28, -21, -14, -7} or {,-70, -60, -50, -40, -30, -20, -10} are countably infinite

Step-by-step explanation:

See the set of integers divisible by 7 or 10,

{7, 14, 21, 28, 35, 42, 49,} Or

{10, 20, 30, 40, 50, 60, 70,}

Can be map one-to-one to {1,2,3,4,5,6,7, The set of natural numbers or positive Integers.

So also, it is applicable in negative integers divisible by 7 or 10.

Therefore, they are countably infinite

A set is uncountable if it contains so many elements that they cannot be put in one-to-one correspondence with the set of natural numbers(Positive Integers). In other words, there is no way that one can count off all elements in the set in such a way that, even though the counting will take forever, you will get to any particular element in a finite amount of time.

WHILE

A set is countable or countably finite if it contains so many elements that they CAN be put in one-to-one correspondence with the set of natural numbers(Positive Integers)

i need the options

step-by-step explanation:

step-by-step explanation:

i found the life tables for the year 2012. 

life table of males at age 30. probability of dying between ages x and x+1

total population:  

29–30 . . . . . . . . . . . . 0.001030

30–31 . . . . . . . . . . . . 0.001061

males:  

29–30 . . . . . . . . . . . . 0.001420

30–31 . . . . . . . . . . . . 0.001448

white population

29–30 . . . . . . . . . . . . 0.001005

30–31 . . . . . . . . . . . . 0.001037

white males

29–30 . . . . . . . . . . . . 0.001372

30–31 . . . . . . . . . . . . 0.001399

non hispanic white population

29–30 . . . . . . . . . . . . 0.001083

30–31 . . . . . . . . . . . . 0.001116

non hispanic white males

29–30 . . . . . . . . . . . . 0.001477

30–31 . . . . . . . . . . . . 0.001503

jacob, non hispanic white male. 30 years old.

probability that jacob lives to be 30 years old. 

since the given probabilities are probabilities of dying, i think we simply subtract it from 1 to get the probability of living. we will use the probability of non hispanic white male.

                                          probability of living to be 30 y.o.

29 - 30 : 1 - 0.001477 = 0.998523

30 - 31 : 1 - 0.001503 = 0.998497