2x + y = -2
5x + 3y = -8
·please help
·solving systems by elimination
·intermediate algebra

x = 2 , y = -6

Step-by-step explanation by elimination:

Solve the following system:

{2 x + y = -2 | (equation 1)

5 x + 3 y = -8 | (equation 2)

Swap equation 1 with equation 2:

{5 x + 3 y = -8 | (equation 1)

2 x + y = -2 | (equation 2)

Subtract 2/5 × (equation 1) from equation 2:

{5 x + 3 y = -8 | (equation 1)

0 x - y/5 = 6/5 | (equation 2)

Multiply equation 2 by 5:

{5 x + 3 y = -8 | (equation 1)

0 x - y = 6 | (equation 2)

Multiply equation 2 by -1:

{5 x + 3 y = -8 | (equation 1)

0 x+y = -6 | (equation 2)

Subtract 3 × (equation 2) from equation 1:

{5 x+0 y = 10 | (equation 1)

0 x+y = -6 | (equation 2)

Divide equation 1 by 5:

{x+0 y = 2 | (equation 1)

0 x+y = -6 | (equation 2)

Collect results:

{x = 2 , y = -6

europa2433

europa2433

step-by-step explanation:

y < -3

step-by-step explanation:

-3y - 2 > 7

-3y -2 + 2 > 7+2

-3y > 9

-3y/-3 < 9/-3   (change the inequality sign when multiplying or dividing by a negative number)

y < -3