Find the area of the shaded region.

let's recall that the area of a rectangle is simply width * length.

the area of the larger "pink" rectangle is therefore (3x+6)(2x+4), and that includes the area of the smaller rectangle inside it.

now, if we get the area of the smaller rectangle, namely (x-3)(x-1) and subtract it from the larger rectangle, we'll in effect be making a hole on the larger rectangle, and what's leftover is the shaded area.

the area of the shaded region is 5x² + 26x + 21

Step-by-step explanation:

The given figure contains a small rectangle and a large rectangle. The difference between the area of the large rectangle and the small rectangle is the shaded area.

The formula for determining the area of a rectangle is expressed as

Area = length × width.

Area of the large rectangle is

(3x + 6)(2x + 4). Expanding the brackets, it becomes

6x² + 12x + 12x + 24

= 6x² + 24x + 24

Area of the small rectangle is

(x - 3)(x - 1). Expanding the brackets, it becomes

x² + x - 3x + 3

= x² - 2x + 3

Therefore, the area of the shaded region is

6x² + 24x + 24 - (x² - 2x + 3)

= 6x² + 24x + 24 - x² + 2x - 3

= 6x² - x² + 24x + 2x + 24 - 3

= 5x² + 26x + 21

x equals 1

step-by-step explanation:

f(4)=f(×)

x=1

none.

step-by-step explanation:

m

1

=

5

m1=5

b

=

−

1

b=-1

find the slope and y-intercept of the second equation.

tap for more

m

2

=

0

m2=0

b

=

−

6

b=-6

compare the slopes

m

m of the two equations.

m

1

=

5

,

m

2

=

0

m1=5,m2=0

compare the two slopes in the decimal form. if the slopes are equal, then the lines are parallel. if the slopes are not equal, then the lines are not parallel.

m

1

=

5

,

m

2

=

0

m1=5,m2=0