A compound shaft consists of brass segment (1) and aluminum segment (2). Segment (1) is a solid brass shaft with an allowable shear stress of 69 MPa. Segment (2) is a solid aluminum shaft with an allowable shear stress of 86 MPa. If a torque of TC = 23900 N-m is applied at C, determine the minimum required diameter of the brass shaft d1 and the aluminum shaft d2.

A) The minimum required diameter of the brass shaft D₁ = 0.00176 m

B) The minimum required diameter of the aluminium shaft D₂ = 0.00142 m

Step-by-step explanation:

Data:

A compound shaft has two segments made of brass and aluminium

Allowable shear stress of Brass = 69 MPa.

allowable sheer stress of Aluminium = 86 MPa.

Torque TC = 23900 N-m

Find: Minimum required diameter of the brass D₁ and Auminium D₂

Solution: see attached picture for workings that shows the break down of the minimum diameter for each segment of the shaft.

54 km / hours

step-by-step explanation:

we need to convert seconds to hours

60 seconds = 1 minutes

60 minutes = 1hour

15 m         60 second   60 minutes

  * *         = 54000 meters/ hour

second     1 minute             1 hour

now we need to convert meters to km

1000 m = 1 km

54000 m       1 km

*   = 54 km / hours

hour               1000m