17 children go on a fairground ride. each car takes 3 children. how may cars are needed for everyone to ride?

6 cars

Step-by-step explanation:

1 car can carry 3 children

Therefore, X cars will carry 17 children.

x cars = 17/3 = 6 ( 5 cars is needed for 15 children and the remaining 2 children will need and extra car. Making a total of 6cars

the direct variation says that:

then the equation is of the form is given by:

            where k is the constant variation.

from the given table:

consider any value of x and m(x)=y

x = 2 and m(x)=y = 3

substitute these value in [1]; we have;

divide both sides by 2 we get;

⇒

check:

put x = -1 and m(x) = -1.5

substitute in the equation:

-1.5 = -1.5                   true

therefore, the function m(x) represents a direct variation

graph of this function as shown below: