A 3-ft wide circular track for a camera dolly is set up for a movie scene. The two rails of the track form concentric circles. The radius of the inner circle is 53 ft. How much farther does a wheel on the outer rail travel than a wheel on the inner rail of the track in one turn? Two circles are concentric. The smaller circle has radius 53 feet. The distance between the two circles is 3 feet. 53 ft 3 ft The wheel on the outer rail travels nothing feet farther than the wheel on the inner rail of the track in one turn.

Outer wheel will cover 18.84 ft more than the inner wheel.

Step-by-step explanation:

We can draw a figure in which two rails are formed by two concentric circles with a distance 3 ft between them.

Outer circle has the radius = (53 + 3) = 56 ft

Radius of the inner circle = 53 ft

In one turn wheel of the outer circle will cover more distance  than the wheel on the inner rail.

So difference in the distance covered by both the wheels = Circumference of outer circle - circumference of inner circle

= 2π(R - r) where R = radius of the outer circle

                            r = radius of the inner circle

Therefore, extra distance covered by the outer wheel = 2π(56 - 53)

= 6π

= 6×(3.14)

= 18.84 ft

9987

step-by-step explanation:

statement #3: proof- ang is congruent to ang ecd : angles are congruent.  

step-by-step explanation:

1: the missing angles in statement #3  

a.) acb  

reason- the reason why the answer is acb is because angle ecd and angle acb are both the same size *that's what the word congruent means this is really simple.  

2: the missing word in reason #3  

c.) vertical  

reason- the reason why the answer is vertical is because the angles in that diagram on figure 2 is slanted, which is vertical, and the e and a both lay on vertical lines. along with the other's, but e and a are the 2 main points you want to focus on. and c is kind of like your starting point, because c is for both angles, not just one.  

i hope that was and understanding.