In a small private school three students are randomly selected from 18 available students what is the probability that
they are the three youngest students

1/ 816  

Step-by-step explanation:

Step 1 :

Given

Total number of students in the school = 18

Number of students randomly selected = 3

Step 2 :

Number of ways in which 3 students can be selected out of 18 students is

C(18,3)  = 18! /(3!(*18-3)!) =  18*17*16/3*2*1 = 816

Number of ways in which 3 students are selected and they are the youngest  = 1

Hence the probability of selecting 3 youngest students from the available students is  1/ C(18,3) = 1/ 816  

step-by-step explanation:

not sure but it may be b, as i said i'm not sure.