Nahee is running around the circular track with equation x2+y2=10000 at a speed of 2.9 meters per second. She starts at the point (0,100) and runs counterclockwise. What are Nahee's coordinates after she has been running for 13 minutes?

The coordinates are (58.1, - 81.4).

Step-by-step explanation:

The distance traveled by Nahee after 13 minutes at the rate of 2.9 m/sec along the arc of the circle with equation x² + y² = 100², will be (13 × 60 × 2.9) = 2262 m

Now, the perimeter of the circle is 2πr = m

Therefore, after traveling three full circles and a half-circle the remaining arc length will be [2262 - (628.57 × 3) - (628.57 ÷ 2)] = 62 m

Therefore, Nahee will finish his run in the fourth quadrant.

Now, the angle made by the arc length of  62 m at the center will be =

So, the angle made with positive x-axis will be (90° - 35.521°) = 54.488°

Now, the coordinates of the finishing point are (x,-y) = (rCos 54.488°, - rSin 54.488°) = (58.1, - 81.4) (Answer)

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?

option c) graph of line going through 1, 4 and 3, 10

step-by-step explanation:

let y equal to margo's coin collection

let x equal to number of years

at the begining x=0, y=1 → point=(x,y)→point=(0,1)

she adds 3 coins per year, then y=1+3x

at x=1, y=1+3(1)=1+3→y=4→point=(x,y)→point=(1,4)

at x=3, y=1+3(3)=1+9→y=10→point=(x,y)→point=(3,10)

the graph of line going through (1, 4) and (3, 10), then the option c is the correct.