HELP PLEASE
solve the right triangle

Part 1)

Part 2)

Part 3)

Step-by-step explanation:

step 1

Find the measure of length side FG

In the right triangle EFG

we know that

----> by SOH (opposite side divided by the hypotenuse)

substitute the given values

step 2

Find the measure of length side EF

In the right triangle EFG

we know that

----> by CAH (adjacent side divided by the hypotenuse)

substitute the given values

step 3

Find the measure of angle G

we know that

---> by complementary angles in a right triangle

c

step-by-step explanation:

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°