37. Rectangle ABCD is graphed on a coordinate
Rectangle A'B'C'D' is formed by translating ABCD 2 units to the right and reflecting it across the y-
axis.
Which statement below would be true in this situation?
A. AB||B'D'
B. CD # A'B'
C. AC # A'B'
D. BD||C'D'

AC # A'B'

Step-by-step explanation:

While solving the above problem one must keep in mind that

Thus, from the figure it becomes clear that

Only statement that comes out true is the third statement which states that AC is not parallel to A’B’

Since the diagonal of a rectangle can not be parallel to one of its side (though the side in question is side of the same rectangle reflected in y axis)

y=3n + 1

step-by-step explanation:

this is wrong because it says the second number is one less and i added one instead

answer: ratio of volume of cone (with 3 times the height and equal diameter) to volume of cylinder is 2 to 1. the value of π is not used.

step-by-step explanation:

radius is diameter/2 = 4.

area of circle is π r^2.

volume of cylinder is height × area of base = hπr^2 = 3(4^2) π = 48π cubic inches.

not knowing the formula for volume of cone, i calculate it using calculus (which is for calculating things).

volume of cone is integral 0 to h area(y) dy. area(y) is π r(y)^2. r(y) runs r to zero as y runs zero to h, r(0) = r, r(h) = 0.

r(y) = r - r/h y

area(y) = π (r - r/h y)^2 = π (r^2 - 2r^2y/h + r^2y^2/h^2) = π r^2(1-2y/h+y^2/h^2)

antiderivative area(y) = π r^2 (y-y^2/h+y^3/(3h^2))

integral 0 to h = π r^2(h-h^2/h+h^3/(3h^2) - (0)) = π r^2(h - h + h/3) = π r^2(h/3) = π/3 r^2 h

volume of this cone is π/3(4^2)18 cubic inches.

= 6 16 π = 96π cubic inches.

cone has twice the volume, 96/48.

cone height is 6 times the cylinder.

ratio of volume formula: π r^2 cancels.

cone over cylinder ratio is 6h/3 to h, 2 to 1.