Three numbers a;b; 9; ... are in geometric sequence. If 1 is subtracted from the first term then
the sequence becomes Arithmetic. Determine the values of a and b.

If you can also solve the other circled question

if a b 9 are in GP

b÷a = 9 ÷ b

b^2 = 9a

if a - 1 b 9 are in AP

2b = a+8

b = a+8÷2

substitute

b is equal to a + 8 by 2 in b square equal to 9 a

(a+8÷2)^2 = 9a

a^2+16a+64 = 36a

a^2 -20a +64 =0

(a-16) (a-4) =0

a= 16 or a=4

when a=16 b= 12

when a=4 b= 6

Value of a and b are given above

bfgbh bhf gfdzf bhgfrdfgbn cvdgsytrghvn ncvhgfdtrseawa hgdrsxcvbgfrewq

step-by-step explanation:

3,6 and 7.

step-by-step explanation:

a) unit place of 37 is 7

so the unit place of cube of 37 will be

7³= 343=3

the answer is 3.

b) unit place of 56 is 6, so the unit place of cube of 56 will be

6³= 216=6

the answer is 6.

c) unit place of 133 is 3, so the unit place of cube of 133 will be

3³= 27= 7.

the answer is 7.