The son is 22 years younger than his father, in 4 years the father is 3 times as old as the son. How old are father and son now? How many years ago was the father 12 times his son?

Step-by-step explanation:

Let the son's present age be x years

Father's present age = (x + 22) years.

Four years after:

Son's age = (x + 4)

Father's age = (x + 22 + 4) =(x + 26) years.

According to the given condition:

Father's age = 3 times the son's age

Hence, now :

Father's age = 29 years

Son's age = 7 years.

Let us move to the next part of the question:

Let y years ago father's age was 12 times his son.

y years ago

son's age = (7 - y) years

Father's age = (29 - y) years

Thus, 5 years ago father's age was 12 times than his son.

is there any photos or whatever?

c(x)= 6x + 3

step-by-step explanation: