Mathematics, 01.03.2020 21:06 victoria6929
A box contains four red balls and eight black balls. Two balls are randomly chosen from the box, and are not
replaced. Let event B be choosing a black ball first and event R be choosing a red ball second.
What are the following probabilities?
P(B) =
P(
RB) =
P(B n R) =
The probability that the first ball chosen is black and the second ball chosen is red is about percent.
Answers: 3
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Add the fractions, and simply the result to lowest terms. 2/3 + 2/7= ?
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A box contains four red balls and eight black balls. Two balls are randomly chosen from the box, and...
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