What is the reminder when (3x^4+2x^3-x^2-14) divided by (x+2)

The remainder is 14

Step-by-step explanation:

The simplest way to find the remainder when 3x^4+2x^3-x^2-14

Is divided by x+2 is to do the following:

3x^4+2x^3-x^2-14 (1)

x+2 = 0 (2)

From equation 2,

x = —2

Substitute the value of x into equation 1. This is illustrated below:

3x^4+2x^3-x^2-14

=> 3(—2)^4 + 2(—2)^3 — (—2)^2 — 14

=> 3(16) + 2(—8) — (4) —14

=> 48 — 16 — 4 — 14

=> 14

The remainder is 14

reminder = 14

Step-by-step explanation:

answer: sorry but i need points

step-by-step explanation:

just sum

10 + 10 = 20