Choosing whatever method is your preference for the given system of equations, solve the following system of equations and show all work.

y = 2x2 + x −1
y = 2x + 2

the solutions are

(3/2, 5)

(- 1, 0)

Step-by-step explanation:

The given system of equations is expressed as

y = 2x² + x - 1- - - - - - - - - - - - - 1

y = 2x + 2- - - - - - - - - - - - - 2

We would apply the method of substitution by substituting equation 2 into equation 1. It becomes

2x + 2 = 2x² + x - 1

2x² + x - 2x - 1 - 2 = 0

2x² - x - 3 = 0

2x² + 2x - 3x - 3 = 0

2x(x + 1) - 3(x + 1)

2x - 3 = 0 or x + 1 = 0

2x = 3

x = 3/2 or x = - 1

Substituting x = 3/2 or x = - 1 into equation 2, it becomes

y = 2 × 3/2 + 2 or y = 2 × - 1 + 2

y = 5 or y = 0