The 5th term of an AP is 11 and the 9th term is 7. Find the 16th term

16th term is 0.

S1ep-by-step explanation:

5th term = a1 + d(5 - 1) = 11    where a1 = first term and d = common difference

9th term = a1 +d(9 - 1) = 7    where a1 = first term and d = common difference.

a1 + 4d = 11

a1 + 8d = 7

Subtracting:

4d - 8d = 11-7

-4d = 4

d = -1.

So a1 = 11 - 4(-1) = 15.

16th term = 15 - 1(16-1)

= 15 - 15

= 0.

a28=58

step-by-step explanation:

a1=a1+(n-1)d

a28= 4+ (28-1)2

a28=4+(27)(2)

a28=4+54

a28=58

the 8 in 8,420 is in the thousands place so it's value is 8 thousand.

the 8 in 6,870 is in the hundreds place so it's value is 8 hundred.

divide 8000 by 800 to find the answer:

8000 / 800 = 10

the 8 in 8,420 is 10 times greater than the 8 in 6,870