Jemboy wants to make his 8 meter square pool into a rectangular one by increasing its length by 2m and decreasing its width by 2m

Side = 8m
He increases length by 2m and reduces width by 2m
(a.) New dimensions will be -
Length = 10m and Width = 6m
(b.) Area = length x breadth (or width)
 here we will use the special product (x+y) (x-y)
length = (x+y) and width = (x-y)
area = (8+2) x (8-2)
            8^(2) - 2^(2) 
            = 60

We know that the square pool has area 8 m^2 what we can get it than this square pool has a side length of sqrt8 =2sqrt2 m 
- increasing the length by 2 m will be the length = 2sqrt2 +2 = 2(sqrt2 +1) m
- decreasing the width by 2m will be the width 2sqrt2 -2 = 2(sqrt2 -1) m

so than what is the question or just these all ?

Aline graph should be used