A line passes through (1, -5) and (-3, 7).
a. Write an equation for the line in point-slope form.
b. Rewrite the equation in slope-intercept form.
A:y-1= (x+5);y = {x+
B:y + 5 = -3(x - 1); y=-3x - 2
C:y-5=(x+1);y = 4x+ 16
D:y - 5= 3(x + 1); y = 3x + 8

Slope-intercept form: y=-3x-2

Point-slope form: y+5=-3(x-1)

Step-by-step explanation:

Slope-intercept form is y=mx+b

Point-slope form is y-y1=m(x-x1)

The slope is (7-(-5))/(-3-1)=12/-4=-3

Now we solve for b, aka. the y-intercept:

-5=-3(1)+b

-5=-3+b

-2=b

So the equation in slope intercept form is y=-3x-2

As for point-slope form, it's y+5=-3(x-1)

.632

step-by-step explanation:

6 * 1/10 = 3/5

3*0.01 = 0.03

3/5 + 0.03 = .63

2*0.002 = .002

.63 + 0.002 = .632

1) 2/5

2) zero=0/1

3) zero=0/2

4) -4/5

5) undefined=3/0