Let A and B be events with =PA0.7, =PB0.2, and =PA and B0.12. (a) Are A and B independent? Explain. (b) Compute PA or B. (c) Are A and B mutually exclusive? Explain. Part 1 of 3 Your Answer is correct (

a) No, b) 0.78, c) No.

Step-by-step explanation:

Since we have given that

P(A) = 0.7

P(B) = 0.2

P(A∩B) = 0.12

(a) Are A and B independent? Explain.

Since P(A).P(B) =

And P(A∩B) = 0.12

P(A∩B) ≠ P(A).P(B)

So, they are not independent.

(b) Compute P(A or B).

(c) Are A and B mutually exclusive? Explain

Since P(A∩B) ≠ 0

So, they are not mutually exclusive.

Hence, a) No, b) 0.78, c) No.

his chances of getting a coin of higher value is 4/19

step-by-step explanation:

let's solve your equation step-by-step.

24−3x=−27

step 1: simplify both sides of the equation.

24−3x=−27

24+−3x=−27

−3x+24=−27

step 2: subtract 24 from both sides.

−3x+24−24=−27−24

−3x=−51

step 3: divide both sides by -3.

−3x

−3

=

−51

−3

x=17

answer:

x=17

step-by-step explanation:

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