A space probe in the shape of the ellipsoid 25 x squared plus y squared plus 4 z squared25x2+y2+4z2equals=2020 enters a planet's atmosphere and its surface begins to heat. After 1 hour, the temperature at the point (x, y,z) on the probe's surface is T(x, y,z)equals=50 x squared plus 4 yz minus 16 z plus 60250x2+4yz−16z+602. Find the hottest point on the probe's surface.

d i think

step-by-step explanation:

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)

11.2

step-by-step explanation:

when doing tangent the tangent of the angle is equal to the opposite side from the angle over the adjacent side to the angle.

tan43 = x / 12

move 12 over by multiplying each side by 12

12tan43 = x

x = about 11.2