Find an equation of the plane passing through (0 comma negative 1 comma 1 )that is orthogonal to the planes 3xplus4ynegative 3zequals0 and negative 3xplus2yplus4zequals5.

The equation of plane is

Step-by-step explanation:

We have to find the equation of plane passing through the point (0,-1,1) and orthogonal to the planes

Thus, we can write:

We will evaluate:

The required plane passes through the point (0,-1,1)

Thus, the equation of plane is

is the required equation of the plane.

i think it's ф or x=6,-6

step-by-step explanation:

-x^2=-36

x^2=-36

ф

or

if you mean by : -(x^2)=-36

it'll be: x^2=36

x=6,x=-6

hope it'll ! have a good day!

you for asking!