Simplify; 1/x^2+5x+6 + 1/x^2+3x+2

pls I need a step by step solution urgently

The simplest form of    is  

Step-by-step explanation:

To add two algebraic fractions do these steps

To simplify

Factorize each denominator

∵ The denominator of the first fraction is x² + 5x + 6

∵ x² = (x)(x)

∵ 6 = (2)(3)

∵ (2)(x) + (3)(x) = 5x ⇒ middle term

∴ x² + 5x + 6 = (x + 2)(x + 3)

∵ The denominator of the second fraction is x² + 3x + 2

∵ x² = (x)(x)

∵ 2 = (2)(1)

∵ (2)(x) + (1)(x) = 3x ⇒ middle term

∴ x² + 3x + 2 = (x + 2)(x + 1)

Find the LCM of the two denominators

∵ The denominators are (x + 2)(x + 3) and (x + 2)(x + 1)

- LCM is all the different factors multiplied together

∴ LCM of them is (x + 1)(x + 2)(x + 3)

- Divide LCM by each denominator

∵ (x + 1)(x + 2)(x + 3) ÷ (x + 2)(x + 3) = (x + 1)

- Multiply the numerator of the first fraction by (x + 1)

∵ (x + 1)(x + 2)(x + 3) ÷ (x + 2)(x + 1) = (x + 3)

- Multiply the numerator of the second fraction by (x + 3)

∴   =

- Add the numerators and write the answer as a single fraction

∴   =

- Factorize the numerator by taking 2 as a common factor

∵ 2x + 4 = 2(x + 2)

∴   =

- Simplify the fraction by dividing up and down by (x + 2)

∴   =

The simplest form of    is  

`1234567890-=/*-qwertyuiop[]asdfghjkl; '\\zxcvbnm,./+ /

i hope this is what you were looking for.

see attached graph