6 assemblies were found to have an average weight of 9.2 ounces with a sample standard deviation is 0.7. Find the 95% confidence interval of the true mean weight

8.6 < µ < 9.8                                

Step-by-step explanation:

Solution:

The general formula for a confidence interval around a population mean (µ) is:

                                   Xbar ± Zα/2[S/√N]  

- Where Xbar is the mean of your sample (= 9.2)

- S is the sample standard deviation (= 0.7)

- N is the number of samples ( = 6)

- Assuming sample size is large enough.

- Z_α/2 is the Z-value in the standard normal table. In this case Z_α/2 = 1.96. (95% confidence interval)

- So your 95% confidence interval is:

                                 µ =Xbar ± Zα/2[S/√N]  

                                 µ = 9.2 ± 1.96[0.7/√6]    

                                 µ = 9.2 ± 0.5601166545  

                            µ is approximately 8.64 or 9.76

- The 95% confidence interval of the true mean weight lies between 8.6 < µ < 9.8                                

since the airplane is moving with constant speed then the distance travelled can be calculated by x=u*t

in km/h would be:

x=640*3.5=2.240 km

in m/s would be:

u=640 km/h= 640.000 m/h =640.000/ 3600 m/s =177.8 m/s

t= 3.5 h= 3.5 * 3600 s=12.600 s

then x=u*t= 177.8*12.600= 2.240.280 m

cut 138 centimeters off

step-by-step explanation:

250-112 = 138