Jackson is building a small rectangular basketball section in his backyard. The length of the section will be 1.25 times the width of the section. Part A Create an equation to represent the area of the basketball section, A, in terms of the width, w. Part B Jackson decides to make the area of the basketball section 245sq feet. What are the dimensions, in feet of the basketball section?

The dimensions of the basketball section are: length of 17.5 feet and width of 14 feet.

Step-by-step explanation:

1. Let's review the information given to us to answer the question correctly:

Length of the small rectangular basketball section = 1.25 times the width

2. Part A. Create an equation to represent the area of the basketball section, A, in terms of the width, w.

Let's recall that the formula of the area of a rectangle is:

Area = Length * Width, therefore:

A = 1.25w * w

A = 1.25w²

Part B. Jackson decides to make the area of the basketball section 245 sq feet. What are the dimensions, in feet of the basketball section?

Let's replace the value given in the equation we created in part A, this way:

A = 1.25w²

245 = 1.25w²

w² = 245/1.25

w² = 196

√w² = √196

w = 14 ⇒ 1.25w = 17.5

The dimensions of the basketball section are: length of 17.5 feet and width of 14 feet.

the figures below are made out of circles, semicircles, quarter … find the area and the perimeter of each figure and give your answers as a completely simplified exact value in terms of π (no approximations). remember that we'll also have to cut whatever areas we get in half, since we're only dealing

step-by-step explanation: