2). A bag contains 50 pieces of gum flavored cherry, grape, and watermelon.
• William will randomly pick a piece of gum.
• The probability of picking cherry is 5.
• The probability of picking watermelon is 10.
3
What is the probability William will pick a piece of grape gum?

37 (i think)

Step-by-step explanation:the probability means the amount of (in this case) the cherry gum or watermelon gum. Add the amount and then subtract the total from the WHOLE number of the WHOLE of the group

(hopefully that made sense)

ummm seems that u didnt post the attachement !

answer:   35 % is the probability of a late departure or an early arrival.

step-by-step explanation:

let l represents the late departure and e represents the early departure.

then, according to the question,

p(l) = 12 %,   p(e) = 27 % and = 4 %

and, we have to find out,

but, we know that,

which is the required equation that will use to find the probability of a late departure or an early departure.

therefore,   the probability of a late departure or an early arrival =   35 %