You collect 100 samples from a large butterfly population. Fifty specimens are dark brown, 20 are speckled, and 30 are white. Coloration in this species of butterfly is controlled by one gene locus: BB individuals are brown, Bb are speckled, and bb are white. What are the allele frequencies for the coloration gene in this population

Total Allele: 100

BB = 100 ;  Bb = 40 ;  bb = 60

Step-by-step explanation:

There are two allele in each gene. Since we have 100 samples of butterfly genes, the total number of allele are 100 x 2 = 200.

For each species:

Dark Brown (BB) → 50 x 2 = 100 allele

Speckled (Bb) → 20 x 2 = 40 allele

White (bb) → 30 x 2 = 60 allele

So, if we let be the frequency of the B allele and be the frequency of the b alleles, then:

6,250

step-by-step explanation:

to get the area, multiply 360 by 160.(57,600)

to find out how many bags of fertilizer it will take, first figure out how many square feet one bag can hold. divide 1000 by 8(125) to get the unit rate(how many square feet one pound of fertilizer can hold)and multiply it by 50(6250). if i haven't made a mistake, that is the answer.