Consider the continuous random variable x, which has a uniform distribution over the interval from 20 to 28. The probability density function has what value in the interval between 20 and 28?a. 1.000 b. 0c. 0.125 d. 0.050

The probability density function is f(x)=0.125.

Step-by-step explanation:

We have he continuous random variable x, which has a uniform distribution over the interval from 20 to 28. We calculate the probability density function has what value in the interval between 20 and 28.  

We use the formula:

We have a=20 and b=28, we get

The probability density function is f(x)=0.125.

the answer is 37

step-by-step explanation:

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.