If you flip three fair coins, what is the probability that you'll get all three heads?

1/8

Step-by-step explanation:

When three fair coins are tossed there is a chance of occuring eight combinations. Hence the probability is 1/8. Each outcome of each flip of a fair coin has a probability of 0.5.

1/8

Step-by-step explanation:

each outcome of a flip is half and half, knowing that a coin has two sides-heads and tails, so to head three heads in a row multiply 0.5 by itself 3 times, to get 1/8:

1/2 * 1/2 * 1/2=1/8,

test this answer out by writing all possibilities down

asdsad

step-by-step explanation:

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)