If you are given the graph of h(x)=log6x, how could you graph m(x)=log6(x+3)?

Translate each point of the graph of h(x) 3 units up.
Translate each point of the graph of h(x) 3 units down.
Translate each point of the graph of h(x) 3 units right.
Translate each point of the graph of h(x) 3 units left.

last option.

Step-by-step explanation:

There are several transformations for a function f(x). Some of them are shown below:

1. If , then the function is translated "k" units up.

2. If , then the function is translated "k" units down.

3. If , then the function is translated "k" units left.

4. If , then the function is translated "k" units right.

In this case you have the following function:

And the function m(x) is obtained by transformating the function h(x). This function is:

Then, based on the transformatios shown before, you can identify that:

Therefore, you can determine that you could graph the function   by translating each point of the graph of the function h(x) 3 units left.

answer:

c 60% on edg

why are you giving so many marks make your marks less and make a question list so that i can understand your question very nicely