What is f(x) = 8x2 + 4x written in vertex form? f(x) = 8(x + one-quarter) squared – one-half f(x) = 8(x + one-quarter) squared – one-sixteenth f(x) = 8(x + one-half) squared – 2 f(x) = 8(x + one-half) squared – 4

i'm not really sure how to answer that

step-by-step explanation:

yx = 36

step-by-step explanation:

cos f = opposite side/ hypotenuse

cos f = yw / yx

we know cos f = 4/9 and yw =16

4/9 = 16/yx

multiply each side by yx

4/9 yx = 16/ yx * yx

4/9 yx = 16

multiply each side by 9/4

9/4 * 4/9 yx = 16 *9/4

yx = 36